The shortest distance between the lines $\large\frac{x}{2}=\frac{y}{2}=\frac{z}{1}$ and $\large\frac{x+2}{-1} = \frac{y-4}{8} =\frac{z-5}{4}$ lies in the interval

Question

$\begin{array}{1 1} (1) [0,1) \\(2) [1,2) \\ (3) (2,3]\\ (4) (3,4] \end{array} $