Let $C$ be a curve given by $y (x) = 1 + \sqrt{4x - 3}, x>\frac{3}{4}.$ If P is a point on $C$, such that the tangent at $P$ has slope $\frac{2}{3},$ then a point through which the normal at $P$ passes is:

Question

$\begin{array}{1 1}(1)\; (2, 3) \\ (2) \; (4, −3)\\ (3) \;(1, 7)\\ (4)\; (3, −4) \end{array}$