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JEEMAIN-2016
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Q)
The solution of the differential equation
d
y
d
x
+
y
2
sec
x
=
tan
2
y
,
where
0
≤
x
<
π
2
,
and
y
(
0
)
=
1
,
is given by
(
1
)
y
=
1
−
x
sec
x
+
tan
x
(
2
)
y
2
=
1
+
x
sec
x
+
tan
x
(
3
)
y
2
=
1
−
x
sec
x
+
tan
x
(
4
)
y
=
1
+
x
sec
x
+
tan
x
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