A straight line through origin $O$ meets the lines $3y=10−4x$ and $8x+6y+5=0$ at points $A$ and $B$ respectively. Then $O$ divides the segment $AB$ in the ratio :

Question

$\begin{array}{1 1} (1)\; 2 : 3 \\(2)\; 1 : 2\\ (3)\; 4 : 1 \\(4)\; 3 : 4 \end{array}$