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The moment of inertia of a uniform cylinder of length l and radius R about its perpendicular bisector is $I$. What is the ratio $\large\frac{l}{R}$ such that the moment of inertia is minimum ?

$\begin{array}{1 1}(1) \sqrt{\large\frac{3}{2}} \\(2) \large\frac{\sqrt 3}{2} \\(3) 1 \\(4) \large\frac{3}{\sqrt 2} \end{array} $

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