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CBSE XII
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Physics
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Moving charges and magnetism
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Q)
<div>Derive an expression for the torque acting on a current carrying loop suspended in a uniform ma
(
a
)
→
T
=
→
m
×
→
B
2
(
b
)
→
T
=
→
m
.
→
B
(
c
)
→
T
=
→
m
×
→
B
(
d
)
→
T
=
|
→
m
|
|
→
B
|
cos
θ
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