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JEEMAIN-2017
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Q)
Let
ω
be a complex number such that
2
ω
+
1
=
z
where
z
=
√
−
3
.
[
1
1
1
1
−
ω
2
−
1
ω
2
1
ω
2
ω
7
]
=
3
k
then k is equal to :
(
1
)
z
(
2
)
−
1
(
3
)
1
(
4
)
−
z
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