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Let k be an integer such that the triangle with vertices (k, −3k), (5, k) and (−k, 2) has area 28 sq. units. Then the orthocentre of this triangle is at the point:

$\begin{array}{1 1} (1) \bigg(1,\large\frac{3}{4} \bigg) \\ (2) \bigg(1,\large\frac{-3}{4} \bigg) \\ (3) \bigg(2,\large\frac{1}{2} \bigg) \\ (4) \bigg(2,-\large\frac{1}{2} \bigg) \end{array} $

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