For three events A, B and C, P(Exactly one of A or B occurs) =P(Exactly one of B or C occurs) =P(Exactly one of C or A occurs)= $\large\frac{1}{4}$ and P(All the three events occur simultaneously)=$\large\frac{1}{16}$.Then the probability that at least one of the events occurs, is :

Question

$\begin{array}{1 1} (1) \large\frac{7}{16} \\ (2) \large\frac{7}{64} \\ (3) \large\frac{3}{16} \\ (4) \large\frac{7}{32} \end{array}$