10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HC1. If we take 20 mL of the same solution of NaOH, the amount of HC1 solution (the same solution as before) required to neutralise it will be

Question

$\begin{array}{1 1} (a) 4mL \\ (b) 8 mL \\ (c) 12 mL \\ (d) 16 mL \end{array} $