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# If the set $S={1,2,3...........12}$ is to be partitioned into $3$ sets $A,B,C$ of equal size so that $A\cup B\cup C=S$ and $A\cap B=B\cap C=C\cap A=\phi$, then the no. of ways the partition can be done is

$\begin{array}{1 1}\large\frac{12!}{(3!)^5} \\ \large\frac{12!}{(4!)^3} \\\large\frac{12!}{(3!)^4} \\ \large\frac{12!}{3!(4!)^3} \end{array}$