Q)
Newton's law of cooling is given by $\theta=\theta_0^{\circ}e^{-kt},$ where the excess of temperature at zero time is $0^{\circ}_{\circ}C $ and at time $t$ seconds is $\theta ^{\circ}C $. Determine the rate of change of temperature after $40 s,$ given that $\theta_{\cdot}=16^{\circ}C $ and $k=-0.03.\qquad (e^{1.2}=3.3201)$
1 Answer
...
