This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
$\begin{array}{1 1} d.c.=(\frac{1}{\sqrt3},\frac{1}{\sqrt3},\frac{1}{\sqrt3})\; distance =1units \\d.c.=(1,1,1)\; distance =\frac{1}{\sqrt3}\;units \\d.c.=(\frac{1}{\sqrt3},\frac{1}{\sqrt3},-\frac{1}{\sqrt3}) distance\; =\frac{1}{\sqrt3}\;units \\ d.c.=(\frac{1}{\sqrt3},\frac{1}{\sqrt3},\frac{1}{\sqrt3})\; distance \;=\frac{1}{\sqrt3}units \end{array} $
