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Questions  >>  CBSE XII  >>  Math  >>  Differential Equations
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For the differential equation xydydx=(x+2)(y+2), find the solution curve passing through the point (1,1).

yx+2=log(x2)(y+2)2y+x+2=log(x2)(y2)2yx2=log(x2)(y2)2y+x+2=log(x2)(y+2)2

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