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If$[\overrightarrow{a} + \overrightarrow{b},\overrightarrow{b}+\overrightarrow{c},\overrightarrow{c} + \overrightarrow{a}]=8$ then $[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]$ is

\[\begin{array}{1 1}(1)4&(2)16\\(3)32&(4)-4\end{array}\]

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