Find the general solution $\large\frac{dy}{dx}=$$\sin^{-1}x$

Question

$\begin{array}{1 1}y = x\sin^{-1}x + \sqrt { 1 - x^2} + C \\ y = x\cos^{-1}x - \sqrt { 1 - x^2} + C \\y = x\tan^{-1}x + \sqrt { 1 + x^2} + C \\ y = x\cos^{-1}x + \sqrt { 1 + x^2} + C\end{array} $