The shortest distance between the lines $\large\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\large\frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5}$ is

Question

$$\begin{array}{1 1}(1)\large\frac{2}{\sqrt{3}}&(2)\frac{1}{\sqrt{6}}\\(3)\frac{2}{3}&(4)\frac{1}{2\sqrt{6}}\end{array}$$