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CBSE XII
>>
Math
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Differential Equations
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Q)
Find the general solution
(
e
x
+
e
−
x
)
d
y
−
(
e
x
−
e
−
x
)
d
x
=
0
y
=
log
(
e
x
+
e
−
x
)
+
C
y
=
log
(
e
x
−
e
−
x
)
+
C
y
=
x
log
(
e
x
)
+
C
y
=
1
−
log
(
e
x
+
e
−
x
)
+
C
Share
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