The normal to the rectangular hyperbola $xy=9$ at$(6,\frac{3}{2})$ meets the curve again at

Question

$$\begin{array}{1 1}(1)\bigg(\frac{3}{8},24\bigg)&(2)\bigg(-24,\frac{-3}{8}\bigg)\\(3)\bigg(\frac{-3}{8},-24\bigg)&(4)\bigg(24,\frac{3}{8}\bigg)\end{array}$$