Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

The surface area of the solid of revolution of the region bounded by $y=2x,x=0$ and $x=2$ about $x$-axis is

\[\begin{array}{1 1}(1)8\sqrt{5}\pi&(2)2\sqrt{5}\pi\\(3)\sqrt{5}\pi&(4)4\sqrt{5}\pi\end{array}\]

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...