If $f:R\rightarrow R$ is defined as $f(x)=3x-5$, then $f^{-1}(x)$ = ?

Question

(A) $\large\frac{x+5}{3}$

(B) $\large\frac{1}{3x-5}$

(C) does not exist because $f$ is not one to one.

(D) does not exist because $f$ is not onto.