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Recent questions tagged gausss-law
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The region between two concentric shells of radii a and b $\;(b > a)\;$ contains volume charge density $\;\rho(r)=\large\frac{C}{r}\;$ , where C is a constant and r is the radial distance , as shown in figure . A point charge q is placed at the origin , r=0 . Find the value of C for which the electric field in the region between the spheres is constant.
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
difficult
asked
Feb 18, 2014
by
yamini.v
1
answer
Consider a block of conducting material of resistivity $ \rho$ shown in the figure. Current I enters at A and leaves from D. We apply superposition principle to find voltage $ \Delta V$ developed between B and C. The calculation is done in the following steps. \[\] (i) Take current I entering from A and assume it to spread over a hemispherical surface in the block. \[\] Calculate field E(r) at distance r from A by using ohm's law $E= \rho j$, where j is the current per unit area at r. \[\] (iii) From the r dependence of E(r) obtain the potential V(r) at r. \[\] (iv) Repeat (i), (ii) and (iii) for current I leaving D and superpose results for A and D \[\] For current entering at A, the electric field at a distance r from A is
jeemain
physics
current-electricity
cbse
class12
ch5
ohms-law
gausss-law
medium
asked
Feb 14, 2014
by
thanvigandhi_1
1
answer
A point charge q is placed on the top of a cone of serni-vertex angle $\;\theta\; $ Find the electric flux through the base of the cone
jeemain
physics
class12
electric-charges-and-fields
electrostatics
gausss-law
difficult
asked
Feb 14, 2014
by
yamini.v
1
answer
Four dipols each of magnitudes of charges $\;\pm q\;$ are placed inside a sphere . The total flux of $\overrightarrow{E}\;$ coming out of the sphere is
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Feb 3, 2014
by
yamini.v
1
answer
If the electric flux entering and leaving an enclosed surface is $\phi_{1}\;and\;\phi_{2}\;.$ The charge inside the surface will be
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Feb 3, 2014
by
yamini.v
1
answer
Distribution of charges is shown in figure . The flux of electric field due to these charges through the surface is
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Jan 30, 2014
by
yamini.v
1
answer
A $\;Q \;\mu C\;$ is placed at the centre of a cube. The flux coming from any surface will be
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Jan 30, 2014
by
yamini.v
1
answer
Given electric field $ \overrightarrow {E} =[1 \times (d + x) \hat i +E_0 \hat j ] N/c$. If a closed surface as shown below is considered , find the change enclosed.
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
difficult
asked
Jan 15, 2014
by
meena.p
1
answer
A point charge Q is placed at the centre of an imaginary Gaussian surface. Find flux through curved surface.
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
difficult
asked
Jan 13, 2014
by
meena.p
1
answer
A charge Q is placed at a distance $D( > R)$ above the centre of disk of radius R The magnitude of flux through disk is $\phi$ . Now a hemispherical shell of radius R is put above the disk to form a closed surface. The flux through the closed surface, if direction of area vector along outward normal is +ve, is :
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
medium
asked
Jan 10, 2014
by
meena.p
1
answer
A circular ring of radius R has charge Q distributed uniformly on it. If a space of radius R, has its centre lying on boundary of the ring, then flux coming out of sphere will be :
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
medium
asked
Jan 9, 2014
by
meena.p
1
answer
A charge q is placed at centre of cube of side l. The electric flux through one face of cube will be :
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Jan 8, 2014
by
meena.p
1
answer
Total electric flux coming out of unit positive charge put in air is :
jeemain
physics
class12
ch1
electrostatics
electric-charges-and-fields
gausss-law
easy
asked
Jan 3, 2014
by
meena.p
1
answer
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