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Q)

Work done in increasing the length of $1\;m$ long wire of cross-sectional area $1\;mm^2$ through $1\;mm$ is $y=2 \times 10^{11}N/m^2$

\[\begin {array} {1 1} (a)\;250\;J \\ (b)\;10\;J \\ (c)\;5\;J \\ (d)\;0.1\;J \end {array}\]

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