Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If $\rho$ is density of the material of a wire and $\sigma$ is the breaking stress. The greatest length of wire that can hang freely without breaking is

\[\begin {array} {1 1} (a)\;\frac{2 \sigma}{\rho g} \\ (b)\;\frac{\rho}{\sigma g} \\ (c)\;\frac{\rho g}{2 \sigma} \\ (d)\;\frac{\sigma}{\rho g}\end {array}\]
Can you answer this question?

1 Answer

0 votes
Maximum stress will be at the point of suspension.
Stree $=\large\frac{weight}{Area}$
Let L be the maximum length that can be hing .
$\sigma = \Large\frac{AL\rho g}{A}$
$L= \large\frac{\sigma}{\rho g}$
Hence d is the coprrect answer.


answered Oct 7, 2013 by meena.p
edited Feb 18, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App