logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Find the values of \[ sin^{-1} \bigg( sin \frac{2\pi}{3} \bigg) \]

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • $sin(\pi - x) = sinx$
  • The range of the principal value of $\sin^{-1}x$ is $\left [ -\frac{\pi}{2}, \frac{\pi}{2} \right ]$
Given $sin^{-1} \bigg( sin \frac{2\pi}{3} \bigg)$
\(sin\frac{2\pi}{3}=sin(\pi-\frac{\pi}{3})\)
We know that $sin(\pi - x) = sinx \Rightarrow sin \frac{2\pi}{3} = sin \frac{\pi}{3}$
The given expression becomes $sin^{-1} sin \frac{\pi}{3}$ which is $= \frac{\pi}{3}$
answered Feb 23, 2013 by thanvigandhi_1
edited Mar 14, 2013 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...