Recent questions and answers in Inverse Trigonometric Functions

tan^-1 + cos^-1(-1/2) + sin^-1(-1/2)

answered Nov 24, 2018 by gujjarkavitakasana

1 answer

Evaluate : $\tan^{-1} (1) + cos^{-1} ( \frac{-1}{2} )+ \sin^{-1} (\frac{-1}{2})$

answered Jul 16, 2018 by punitakharb430

2 answers

Find the value of $\tan^{-1} (\frac{x}{y}) - \tan^{-1}(\frac{x-y}{x+y})$

answered Nov 30, 2016 by priyanka.c

1 answer

Evaluate :$\sec^2 (\tan^{-1}(2)) + cosec^2(\cot^{-1}(3))$

answered Nov 23, 2016 by priyanka.c

1 answer

Evaluate : $\tan \frac{1}{2} (\cos^{-1} \frac{\sqrt 5}{3})$

answered Nov 22, 2016 by priyanka.c

1 answer

Evaluate $tan^{-1} (\frac{\cos x}{1-\sin x}), \;\; \; -\frac{\pi}{2} < x < \frac{\pi}{2}$

answered Nov 20, 2016 by priyanka.c

1 answer

Differentiate $\tan^-1 \frac{[\sqrt{1+x^2} + 1}{x}], x \neq 0$

answered Nov 18, 2016 by priyanka.c

1 answer

If $\cos^{-1} x + cos^{-1} y + cos^{-1} z = \pi $ , Evaluate $x^2 + y^2 + z^2 + 2xyz$

answered Nov 17, 2016 by priyanka.c

1 answer

$\tan ^{-1}x +\tan^{-1} \frac{2x}{1-x^2} = 3 \tan ^{-1}(x) \;, |x| < \frac{1}{\sqrt 3}$ . Is this true ? Justify.

answered Nov 16, 2016 by priyanka.c

1 answer

Prove that $\tan^{-1}{\frac{1}{4}}+\tan^{-1}{\frac{2}{9}}=\sin^{-1}{\frac{1}{\sqrt 5}}$

answered Jul 9, 2014 by balaji.thirumalai

1 answer

Prove that \[ 2sin^{-1} \frac{3}{5} = tan^{-1} \frac{24}{7} \]

answered Jul 9, 2014 by balaji.thirumalai

1 answer

Show that $\tan({\frac{1}{2}}\sin^{-1}{\frac{3}{4}})=\frac{4-\sqrt 7}{3}$

answered Jun 12, 2014 by balaji.thirumalai

1 answer

If $2\tan^{-1}(\cos x)=\tan^{-1}(2cosecx)$,then show that $x=\Large {\frac{\pi}{4}}$

answered Jun 12, 2014 by balaji.thirumalai

1 answer

If $3\tan^{-1}x+4\cot^{-1}x=2\pi$ then $ x$ =?

answered Jan 28, 2014 by rvidyagovindarajan_1

1 answer

Find the value of $\tan({\frac{1}{2}}\sin^{-1}{\frac{1}{4}})$

answered Jan 28, 2014 by rvidyagovindarajan_1

1 answer

Evaluate : $\cos\; \large \bigg( \frac{\pi}{2} -$$ \cos^{-1}\; \large\bigg (-\frac{\sqrt 3}{2}\bigg)\bigg)$

answered Dec 22, 2013 by balaji.thirumalai

1 answer

Solve the equation: $\sin^{-1}(6x) + \sin^{-1}(6\sqrt 3 x) =-\large \frac{\pi}{2}$

answered May 24, 2013 by rvidyagovindarajan_1

1 answer

Solve the following $tan^{-1} \frac{1-x}{1+x} =\frac{1}{2} tan^{-1} x,(x>0)$

answered Mar 21, 2013 by rvidyagovindarajan_1

2 answers

$sin^{-1}\:is\:>\:cos^{-1}x\:in\:which\:interval?$

answered Mar 17, 2013 by rvidyagovindarajan_1

1 answer

What is the value of the function: $\large \frac{1}{4} $$\sin^{-1}\large\frac{2\sqrt 2}{3}$$+\sin^{-1}\large\frac{1}{3} $

answered Mar 14, 2013 by balaji.thirumalai

1 answer

Evaluate $\tan^{-1} \left (\large \frac {{\sqrt {1+x}}-{\sqrt {1-x}}}{{\sqrt {1+x}}+{\sqrt {1-x}}} \right )$$,\frac{-1}{\sqrt2} \leq x \leq 1$

answered Mar 14, 2013 by balaji.thirumalai

1 answer

Evaluate $\cot^{-1} \left ( \large \frac {{\sqrt {1+\sin x}}+{\sqrt {1-\sin x}}}{{\sqrt {1+\sin x}}-{\sqrt {1-\sin x}}} \right ) = \large \frac {x}{2}$$ , x \in \left ( 0, \frac{\pi}{4} \right )$

answered Mar 14, 2013 by balaji.thirumalai

1 answer

Find the value of the following function: $tan^{-1} \frac{1}{5}+ tan^{-1} \frac{1}{7}+tan^{-1}\frac{1}{3}+tan^{-1} \frac{1}{8}$

answered Mar 14, 2013 by balaji.thirumalai

1 answer

Prove the following function: 7.$ tan^{-1}\frac{63}{16} = sin^{-1} \frac{5}{13}+cos^{-1} \frac {3}{5}$

answered Mar 14, 2013 by balaji.thirumalai

1 answer

What does $cos^{-1} \frac {12}{13} +sin^{-1} \frac{3}{5}$ reduce to?

answered Mar 14, 2013 by balaji.thirumalai

1 answer

What does $cos^{-1} \frac {4}{5} +cos^{-1} \frac{12}{13}$ reduce to?

answered Mar 14, 2013 by balaji.thirumalai

1 answer

What does $sin^{-1} \frac{8}{17} +sin^{-1} \frac{3}{5}$ reduce to?

answered Mar 14, 2013 by balaji.thirumalai

1 answer

What does $2sin^{-1} \frac{3}{5}$ reduce to?

answered Mar 14, 2013 by balaji.thirumalai

1 answer