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Q)

In a GP, given that the first term is $ 312 ½ $ and the common ratio is $ 1/2 $ find the sum of the terms of the series to infinity.

$(a)\;625\qquad(b)\;1250\qquad(c)\;312 \frac{1}{2}\qquad(d)\;\infty$

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A)
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it is provided that first term a=625/2

                                            r=1/2

sum to infinity= a/(1-r)

                      =625/2(1-1/2)

                      =1250/2 ===625

            so a is the correct one

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