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Recent questions and answers in Sequence and Series
Questions
>>
JEEMAIN and NEET
>>
Mathematics
>>
Class11
>>
Sequence and Series
In a GP, given that the first term is
312
½
and the common ratio is
1
/
2
find the sum of the terms of the series to infinity.
jeemain
math
class11
unit7
sequences-and-series
medium
answered
May 14, 2017
by
nikunjjain285
1
answer
The sum of 0.2, 0.22, 0.222, 0.2222.....till n terms is given by
jeemain
math
class11
ch9
sequences-and-series
easy
sum-of-n-terms-of-special-series
q93
answered
Sep 16, 2015
by
illusionist.nectar
2
answers
If
a
,
b
,
c
are in
G
P
and equations
a
x
2
+
2
b
x
+
c
=
0
and
d
x
2
+
2
e
x
+
f
=
0
have a common root, then
d
a
,
e
b
,
f
c
are in
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q195
answered
Jan 24, 2014
by
yamini.v
1
answer
If
a
2
a
3
a
1
a
4
=
a
2
+
a
3
a
1
+
a
4
=
3
(
a
2
−
a
3
a
1
−
a
4
)
, then,
a
1
,
a
2
,
a
3
,
a
4
are in
jeemain
math
class11
ch9
sequences-and-series
difficult
relationship-between-ap-and-gm
q194
answered
Jan 24, 2014
by
yamini.v
1
answer
If
(
m
+
n
)
t
h
,
(
n
+
1
)
t
h
,
(
r
+
1
)
t
h
term of an AP are in GP and
m
,
n
,
r
are in HP, then ratio of first term of AP to common difference is
jeemain
math
class11
ch9
sequences-and-series
difficult
relationship-between-ap-and-gm
q193
answered
Jan 24, 2014
by
yamini.v
1
answer
a
x
=
b
y
=
c
z
=
d
t
and
a
,
b
,
c
,
d
are in GP, then
x
,
y
,
z
,
t
are in
jeemain
math
class11
ch9
sequences-and-series
difficult
geometric-progression
q192
answered
Jan 24, 2014
by
yamini.v
1
answer
If sides of
△
A
B
C
(
a
,
b
,
c
)
are in AP,
c
o
t
c
2
equals
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q191
answered
Jan 23, 2014
by
yamini.v
1
answer
If AM and GM of two numbers are in ratio
p
:
q
, then the ratio of two numbers is
jeemain
math
class11
ch9
sequences-and-series
difficult
relationship-between-ap-and-gm
q190
answered
Jan 23, 2014
by
yamini.v
1
answer
Given
1
1
4
+
1
2
4
+
1
3
4
+.....
∞
=
π
4
90
, then the value of
1
1
4
+
1
3
4
+
1
5
4
+....
∞
is
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q189
answered
Jan 23, 2014
by
yamini.v
1
answer
If
a
1
,
a
2
,
a
3
,
.
.
.
.
.
are in HP and
f
(
k
)
=
n
∑
r
=
1
a
r
−
a
k
, then
a
1
f
(
1
)
,
a
2
f
(
2
)
,
a
3
f
(
3
)
,...,
a
n
f
(
n
)
are in
jeemain
math
class11
ch9
sequences-and-series
difficult
harmonic-progression
q188
answered
Jan 23, 2014
by
yamini.v
1
answer
a
1
=
50
and
a
1
+
a
2
+
.
.
.
.
+
a
n
=
n
2
a
n
∀
n
≥
1
, value of
a
50
equal to
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q187
answered
Jan 23, 2014
by
yamini.v
1
answer
If 1 , 3 , 8 are first three terms of an arithmetic - geometric progression (with +ve common difference ) , the sum of next three terms is :
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q186
answered
Jan 23, 2014
by
yamini.v
1
answer
Sum of n terms of the series
1
4
+
7
16
+
37
64
+
175
256
+... is
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q185
answered
Jan 23, 2014
by
yamini.v
1
answer
Sum of the series
2
5
+
3
5
2
+
4
5
3
+
2
5
4
+
3
5
5
+
4
5
6
+
.
.
.
equals:
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q184
answered
Jan 23, 2014
by
yamini.v
1
answer
⊓
∞
n
=
2
n
3
−
1
n
3
+
1
equals
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q183
answered
Jan 23, 2014
by
yamini.v
1
answer
If
S
n
=
1
6
n
(
n
+
1
)
(
n
+
2
)
∀
n
≥
1
, then
lim
n
→
∞
n
∑
r
=
1
1
a
r
equals
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q182
answered
Jan 23, 2014
by
yamini.v
1
answer
Given
1
2
+
2
2
+
3
2
+
.
.
.
.
+
2003
2
=
(
2003
)
(
4007
)
(
334
)
and
(
1
)
(
2003
)
+
(
2
)
(
2002
)
+
(
3
)
(
2001
)
+
.
.
.
.
+
(
2003
)
(
1
)
=
(
2003
)
(
334
)
(
x
)
then value of
x
is
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q176
answered
Jan 23, 2014
by
yamini.v
1
answer
If
a
n
=
n
∑
k
=
1
1
k
(
n
+
1
−
k
)
, then for
n
≥
2
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q181
answered
Jan 23, 2014
by
yamini.v
1
answer
If
f
1
=
f
2
=
1
and thereafter
f
n
+
2
=
f
n
+
1
+
f
n
for all
n
∈
N
. Find
∞
∑
n
=
2
1
f
n
+
1
.
f
n
−
1
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q180
answered
Jan 23, 2014
by
yamini.v
1
answer
S
1
,
S
2
,
.
.
.
.
.
S
n
are sums of infinite geometric series with first term
1
,
2
,
3
,
.
.
.
n
and common ratio
1
2
,
1
3
,...
1
n
+
1
respectively. Find
n
∑
r
=
1
S
r
.
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q179
answered
Jan 23, 2014
by
yamini.v
1
answer
Find sum upto n terms:
3
1
2
.2
2
+
5
2
2
.3
2
+
7
3
2
.4
2
+....
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q178
answered
Jan 23, 2014
by
yamini.v
1
answer
Find the sum of the numbers in the
n
t
h
set:
(
1
)
,
(
2
,
3
)
,
(
4
,
5
,
6
)
,
(
7
,
8
,
9
,
10
)
.....
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q177
answered
Jan 23, 2014
by
yamini.v
1
answer
Find sum of first n terms of series :
1
+
1
1
+
2
+
1
1
+
2
+
3
+
.
.
.
.
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q176
answered
Jan 23, 2014
by
yamini.v
1
answer
Evaluate sum to n terms
1.1
+
2.01
+
3.001
+
.
.
.
.
.
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q175
answered
Jan 23, 2014
by
yamini.v
1
answer
For an AP with first term
a
and common difference
d
, if
S
n
x
S
x
(
S
r
denotes sum upto
r
term
)
is independent of
x
then,
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q174
answered
Jan 23, 2014
by
yamini.v
1
answer
If
l
o
g
2
5.2
x
+
1
,
l
o
g
4
2
x
−
1
+
1
and 1 are in HP, then
jeemain
math
class11
ch9
sequences-and-series
difficult
harmonic-progression
q173
answered
Jan 23, 2014
by
yamini.v
1
answer
If the sum of first n terms of an AP is half the sum of next n terms, then
S
4
n
S
n
equals
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q172
answered
Jan 23, 2014
by
yamini.v
1
answer
Sum of the series
S
=
4
7
−
5
7
2
+
4
7
3
−
5
7
4
+
.
.
.
.
.
∞
is :
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q171
answered
Jan 23, 2014
by
yamini.v
1
answer
Given
a
n
=
n
∑
k
=
1
√
1
+
1
k
2
+
1
(
k
+
1
)
2
the value of
a
5
is
jeemain
math
class11
ch9
sequences-and-series
difficult
sum-of-n-terms-of-special-series
q170
answered
Jan 23, 2014
by
yamini.v
1
answer
a
,
x
,
y
,
z
,
b
are in AP such that
x
+
y
+
z
=
15
and
a
,
α
,
β
,
y
,
b
are in HP such that
1
α
+
1
β
+
1
γ
=
5
3
. Find
a
,
(
a
>
b
)
.
jeemain
math
class11
ch9
sequences-and-series
difficult
arithmetic-progression
q169
answered
Jan 23, 2014
by
yamini.v
1
answer
The sum of three terms of a strictly increasing GP is
α
S
and sum of their squares is
S
2
.
α
2
lies in
jeemain
math
class11
ch9
sequences-and-series
difficult
geometric-progression
q168
answered
Jan 23, 2014
by
yamini.v
1
answer
Given for every
n
∈
N
(
1
2
−
a
1
)
+
(
1
2
−
a
2
)
+
.
.
.
.
.
.
.
+
(
n
2
−
a
n
)
=
1
3
n
(
n
2
−
1
)
t
h
e
a
n
equals
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q167
answered
Jan 23, 2014
by
yamini.v
1
answer
Given
t
r
=
1
2
+
2
2
+
.
.
.
.
.
.
.
r
2
and
t
1
+
t
2
+
t
3
+
.
.
.
t
n
=
k
12
n
(
n
+
1
)
(
n
+
2
)
the value of k will be
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q166
answered
Jan 23, 2014
by
yamini.v
1
answer
Four geometric means are inserted between
2
9
−
1
a
n
d
2
9
+
1
.
The product of these means is :
jeemain
math
class11
unit7
sequences-and-series
medium
q165
asked
Jan 22, 2014
by
yamini.v
0
answers
p
(
x
)
=
1
+
x
2
+
x
4
+
.
.
.
x
2
n
−
2
1
+
x
+
x
2
+
.
.
.
+
x
n
−
1
is a polynomial in x , then n must be
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q164
answered
Jan 22, 2014
by
yamini.v
1
answer
If in an AP ,
a
n
denotes the
n
t
h
term and
a
p
=
1
q
and
a
q
=
1
p
the root of the equation
jeemain
math
class11
ch9
sequences-and-series
medium
arithmetic-progression
q163
answered
Jan 22, 2014
by
yamini.v
1
answer
If
a
1
,
a
2
,
.
.
.
.
a
n
are in HP then
a
1
a
2
+
a
3
+
.
.
+
a
n
,
a
2
a
1
+
a
3
+
.
.
.
+
a
n
,
a
3
a
1
+
a
2
+
a
4
+
.
.
.
+
a
n
,
.
.
.
.
.
a
n
a
1
+
a
2
+
.
.
.
.
+
a
n
−
1
are in
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q162
answered
Jan 22, 2014
by
yamini.v
1
answer
If a , b , c are in AP and A.G are arithmetic and geometric mean , between a and b while
A
|
a
n
d
G
|
are A.M and G.M between B and C . then
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q161
answered
Jan 22, 2014
by
yamini.v
1
answer
If
a
,
b
,
c
are three numbers in GP . and
a
+
x
,
b
+
x
,
c
+
x
are in HP then
x
equals
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q160
answered
Jan 22, 2014
by
yamini.v
1
answer
If a , b , c , d are in HP
d
−
2
−
a
−
2
c
−
2
−
b
−
2
equals
jeemain
math
class11
ch9
sequences-and-series
medium
harmonic-progression
q159
answered
Jan 22, 2014
by
yamini.v
1
answer
If x , y , z are in GP then ,
1
x
2
−
y
2
+
1
y
2
equals
jeemain
math
class11
ch9
sequences-and-series
medium
geometric-progression
q158
answered
Jan 22, 2014
by
yamini.v
1
answer
For
n
∈
N
n
≥
25
, Let A.G.H be A.M ,G.M and H.M of 25 and n . what is the least value of n such that A.G.H are all natural numbers greater than 25 .
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q157
answered
Jan 22, 2014
by
yamini.v
1
answer
α
&
β
are +ve roots of
x
2
−
2
a
x
+
a
b
=
0
then for
n
∈
N
(
0
<
b
<
a
)
S
n
=
1
+
2
(
b
a
)
+
3
(
b
a
)
2
+
.
.
.
+
n
(
b
a
)
n
−
1
can not exceed .
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q156
answered
Jan 22, 2014
by
yamini.v
1
answer
If a,b,c are real and
4
a
2
+
9
b
2
+
16
c
2
−
6
a
b
−
12
b
c
−
8
a
c
=
0
the a,b,c are in
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q155
answered
Jan 22, 2014
by
yamini.v
1
answer
I
f
a
1
=
1
2
,
a
k
+
1
=
a
2
k
+
a
k
∀
k
≥
1
a
n
d
x
n
=
1
a
1
+
1
+
1
a
2
+
1
+
.
.
.
1
a
n
+
1
t
h
e
v
a
l
u
e
o
f
[
x
50
]
i
s
(
[
.
]
r
e
p
r
e
s
e
n
t
s
g
r
e
a
t
e
s
t
i
n
t
e
g
e
r
f
u
n
c
t
i
o
n
)
)
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q154
answered
Jan 22, 2014
by
yamini.v
1
answer
If
a
1
=
1
,
a
n
+
1
=
2
a
n
+
1
then ,
a
n
+
1
equals
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q153
answered
Jan 22, 2014
by
yamini.v
1
answer
Sum of n terms of series
S
=
1
2
+
2
(
2
)
2
+
3
2
+
2
(
4
)
2
+
5
2
+
.
.
.
.
when n is even is :
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q152
answered
Jan 22, 2014
by
yamini.v
1
answer
If
a
1
,
a
2
,
a
3
(
a
1
≥
0
)
are in GP with common ratio r . the value of r for which inequality
a
3
≥
4
a
2
−
3
a
1
holds is given by ,
jeemain
math
class11
ch9
sequences-and-series
medium
geometric-progression
q151
answered
Jan 22, 2014
by
yamini.v
1
answer
If
p
x
2
+
q
x
≥
r
for every +ve x
(
p
>
0
,
q
>
0
)
,
then
27
p
q
2
can not be less than
jeemain
math
class11
ch9
sequences-and-series
medium
relationship-between-ap-and-gm
q150
answered
Jan 22, 2014
by
yamini.v
1
answer
A
1
,
A
2
,
.
.
.
.
A
n
are fixed +ve real number such that
A
1
.
A
2
.
.
A
n
=
k
, then
A
1
+
2
A
2
+
.
.
.
n
A
n
can not be than :
jeemain
math
class11
ch9
sequences-and-series
medium
sum-of-n-terms-of-special-series
q149
answered
Jan 22, 2014
by
yamini.v
1
answer
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