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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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Find the sum of series 4 + 44 + 444 + 4444 +------upto n terms.

$\begin{array}{1 1} \infty \\ \frac{4}{9}[\frac{10(10^n-1)}{9}-n] \\44^4-4 \\ \frac{4(4^n-1)}{3}\end{array}$

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Answer : (b) $\frac{4}{9}[\frac{10(10^n-1)}{9}-n]$
Explanation: S=4+44+444+-------n terms
answered Dec 31, 2013 by yamini.v

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