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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Sequence and Series

If the p and q are roots of the equation $x^2-7x+A=0\;\xi\;r\;\xi\;s$ are roots of equation $x^2-19x+B=0,$ find the values of $A\;\xi\;B$ if p,q,r,s are in AP.


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Answer : (d) A=10 , B=88
Explanation : Equations $\;x^2-7x+A=0\qquad\;x^2-19x+B=0$
$Since\; p,q,r,s \;are\;in\;AP$
$AP\; is\; 2,5,8,11.$


answered Jan 2, 2014 by yamini.v
edited Jan 2, 2014 by yamini.v

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