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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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The third term of a GP is 2. Calculate the product of the first 5 terms.

$\begin{array}{1 1} 256 \\ 64\\ 32 \\ 16 \end{array}$

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Answer : (c) 32
Explanation : Let terms of GP= $a,ar,ar^2,ar^3,ar^4$
$ar^2=2$
$product \;of\; 5 terms\quad\;a*ar*ar^2*ar^3*ar^4=a^5r^{10}$
$(ar^2)^5=2^5=32.$
answered Jan 2, 2014 by yamini.v
 

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