# The angles of a quadrilateral are in AP whose common difference is $10^0$. Find the angles.

$\begin{array}{1 1} 60,70,80,90 \\ 80,90,100,110 \\ 85,95,105,115 \\ 75,85,95,105 \end{array}$

$Explanation :\; Let\;the\;4\;angles\;be\;a,a+d,a+2d,a+3d$
$a+a+10+a+20+a+30=360$
$4a=360-60=300$
$a=75^0$
$angles\;are\;75,85,95,105.$