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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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The angles of a quadrilateral are in AP whose common difference is $10^0$. Find the angles.

$\begin{array}{1 1} 60,70,80,90 \\ 80,90,100,110 \\ 85,95,105,115 \\ 75,85,95,105 \end{array}$

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Answer : (d) 75,85,95,105
$Explanation :\; Let\;the\;4\;angles\;be\;a,a+d,a+2d,a+3d $
$a+a+10+a+20+a+30=360$
$4a=360-60=300$
$a=75^0$
$angles\;are\;75,85,95,105.$
answered Jan 3, 2014 by yamini.v
 

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