The angles of a quadrilateral are in AP whose common difference is $10^0$. Find the angles.

Question

$\begin{array}{1 1} 60,70,80,90 \\ 80,90,100,110 \\ 85,95,105,115 \\ 75,85,95,105 \end{array}$

Answer 1

Answer : (d) 75,85,95,105

$Explanation :\; Let\;the\;4\;angles\;be\;a,a+d,a+2d,a+3d $

$a+a+10+a+20+a+30=360$

$4a=360-60=300$

$a=75^0$

$angles\;are\;75,85,95,105.$