logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
0 votes

$(1-2y)\;(1+3x+9x^2+27x^3+81x^4+243x^5+729x^6)$ = $(1-64y^6)$, $(y\;\neq\;1)$, then $\frac{x}{y}$ is

$(a)\;\frac{3}{2}\qquad(b)\;\frac{2}{3}\qquad(c)\;\frac{4}{9}\qquad(d)\;\frac{9}{4}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : (b) $\;\frac{2}{3}$
Explanation : $\;(1-2y)\;(\frac{1-(3x)^6}{1-3x})=(1-64y^6)$
One possible value is $\;2y=3x$
$\frac{x}{y}=\frac{2}{3}.$
answered Jan 21, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...