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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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Sum of n terms of series $\;S=1^2+2(2)^2+3^2+2(4)^2+5^2+\;....\;$ when n is even is :


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Answer : (d) $\;\frac{1}{2}n(n+1)^2$
Explanation : $Let \;n=2m$
answered Jan 22, 2014 by yamini.v
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