$\begin{array}{1 1}(A)\;9.8\times 10^{10}\\(B)\;9.8\times 10^9\\(C)\;4.9\times 10^{16}\\(D)\;\text{None}\end{array} $

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The pressure change=Sgh

$S_{water}=10^3kg/m^3$

$P=10^3\times 9.8\times 500$

$\Rightarrow 49\times 10^5$

$\Rightarrow 4.9\times 10^6N/m^2$

$\large\frac{\Delta V}{V}$$=5\times 10^{-4}$

$B=\large\frac{P}{\Large\frac{\Delta V}{V}}$

$\;\;\;=\large\frac{4.9\times 10^6}{5\times 10^{-4}}$

$\;\;\;=0.98\times 10^{10}$

$\;\;\;=9.8\times 10^9$

Hence (B) is the correct answer.

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