$\begin{array}{1 1}(A)\;50N\\(B)\;94N\\(C)\;107N\\(D)\;25N\end{array} $

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Given $\Delta x=.25cm$

$l=2cm$

$\theta=\large\frac{.25}{2}=\frac{1}{8}$

$\eta=5\times 10^5$

$\eta=(\large\frac{F}{a})\times \frac{l}{\Delta x}$

$5\times 10^5=\large\frac{F}{3\times 5\times 10^{-4}}\times \frac{2}{.25}$

$F=\large\frac{5\times 10^5\times 3\times 5\times 10^{-4}}{8}$

$\;\;\;=93.75N$

$\;\;\;\approx 94N$

Hence (B) is the correct answer.

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