$\begin{array}{1 1}(A)\;2\%\\(B)\;.5\%\\(C)\;1\%\\(D)\;3\%\end{array} $

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As $V=\large\frac{4}{3}$$\pi R^3$

$\large\frac{\Delta V}{V}=\frac{3\Delta R}{R}$

$B=\large\frac{P}{\Delta V/V}$

$P=\large\frac{mg}{A}$

$\;\;\;=\large\frac{30\times 9.8}{10^2\times 10^{-4}}$

$\;\;\;=3\times 9.8\times 10^3N/m^2$

$\large\frac{\Delta V}{V}=\frac{P}{B}$

$\Rightarrow \large\frac{3\times 9.8\times 10^3}{2\times 10^6}$

$\Rightarrow 1.47\times 10^{-2}$

$\large\frac{\Delta R}{R}=\frac{1}{3}\frac{\Delta V}{V}$

$\Rightarrow .49\times 10^{-2}$

$\Rightarrow .49\%$

$\Rightarrow \approx .5\%$

Hence (B) is the correct answer.

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