Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Find the density of material under a pressure $3\times 10^8N/m^2$ .Given the density of material $800Kg/m^3$.Bulk modulus of material $9\times 10^9N/m^2$.

$\begin{array}{1 1}(A)\;826Kg/m^3\\(B)\;774Kg/m^3\\(C)\;878Kg/m^3\\(D)\;\text{None of above}\end{array} $

Can you answer this question?

1 Answer

0 votes
As density =$\large\frac{\text{mass}}{\text{volume}}$
$\large\frac{\Delta S}{S}=-\frac{\Delta V}{V}$
As pressure increase,volume decrease and density of material increases
We know $\large\frac{\Delta V}{V}=\frac{\rho}{B}$
$\Rightarrow \large\frac{3\times 10^8}{9\times 10^9}$
$\Rightarrow \large\frac{1}{3}$$\times 10^{-1}$
$\large\frac{\Delta S}{S}=\frac{1}{3}$$\times 10^{-1}$
$\Delta S=\large\frac{80}{3}$$=26.67Kg/m^3$
$\Rightarrow 826.67Kg/m^3$
Hence (A) is the correct answer.
answered May 8, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App