$\begin{array}{1 1}(A)\;\text{Perimeter of the hole}\\(B)\;\text{Density of the liquid}\\(C)\;\text{Height of the liquid from the hole}\\(D)\;\text{Acceleration due to gravity}\end{array} $

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Applying Bernoulli's theorem to A & B

$\rho_A+\large\frac{1}{2}$$\rho V_A^2+\rho gh=\rho_B+\large\frac{1}{2}$$\rho V_B^2$

$\rho_o+\large\frac{1}{2}$$\rho V_A^2+\rho gh=\rho_o+\large\frac{1}{2}$$\rho V_B^2$

$\large\frac{1}{2}$$\rho V_A^2+\rho g h=\large\frac{1}{2}$$\rho V_B^2$------(1)

$A_AV_A=A_BV_B$

$\pi R^2V_A=A_BV_B$

$V_A=\large\frac{r^2}{R^2}$$V_B$----(2)

From (1) & (2)

$\large\frac{1}{2}$$\rho (\large\frac{r^2}{R^2}$$V_B)^2+\rho gh=\large\frac{\rho}{2}$$V_B^2$

$\large\frac{\rho}{2}$$V_B^2-\large\frac{1}{2}$$\rho (\large\frac{r^2}{R^2}$$V_B)^2=\rho gh$

Hence depending on f,r,R,h & g$

Hence (B) is the correct answer.

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