$\begin{array}{1 1}(A)\;0.7\\(B)\;0.8\\(C)\;1\\(D)\;1.2\end{array} $

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Height of the spirit column $h_1=12.5cm=0.125m$

Height of the water column $h_2=10cm=0.1m$

$\rho _0=P_{atm}$

$\rho _1$=Density of spirit

$\rho _2$=Density of water

Now $\rho_B=\rho_D$

$\Rightarrow P_0+h_1\rho_1g=P_0+h_2\rho_2g$

$\Rightarrow \large\frac{\rho_1}{\rho_2}=\frac{h_2}{h_1}$$=0.8$

Put the value & get

Specific gravity of spirit =0.8

Hence (B) is the correct answer.

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