$\begin{array}{1 1}(A)\;1\times 10^3N\\(B)\;1.45\times 10^3N\\(C)\;1.51\times 10^3N\\(D)\;2.1\times 10^4N\end{array} $

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$V_1=70m/s$

$V_2=63m/s$

Area of wing $A=2.5m^2$

Density of air $\rho=1.3Kgm^{-3}$

According to Bernoulli's theorem

$P_1+\large\frac{1}{2}$$\rho V_1^2$$=P_2+\large\frac{1}{2}$$\rho V_2^2$

$P_2-P_1=\large\frac{1}{2}$$\rho (V_1^2-V_2^2)$

Where $P_1$ & $P_2$ is the pressure on the upper & lower surface of the ring respectively.

Lift on the wing =$(P_2-P_1)A$

$\Rightarrow \large\frac{1}{2}$$\rho (V_1^2-V_2^2)A$

$\Rightarrow \large\frac{1}{2}$$\times 1.3 (70^2-63^2)\times 2.5$

$\Rightarrow 1.51\times 10^3N$

Therefore lift on the wing of the aeroplane =$1.51\times 10^3N$

Hence (C) is the correct answer.

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