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A parallel plate capacitor with air between the plates has a capacitance of $9\: pF$. The separation between the plates is $d$ . The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant $k_1=3$ and thickness $ \large\frac{d}{3}$ while the other has dielectric constant $k_2=6$ and thickness $ \large\frac{2d}{3}$. Capacitance of the capacitor is now
jeemain
physics
cbse
class12
ch4
electrostatics
electrostatic-potential-and-capacitance
effect
-of-dielectric-on-capacitance
medium
asked
Feb 14, 2014
by
thanvigandhi_1
1
answer
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