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Recent questions tagged long-answer-type-question
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Questions from:
Find the equations of the lines through the point of intersection of the lines $x-y+1=0 $ and $ 2x-3y+5 = 0$ and whose distance from the point (3, 2) is $ \large\frac{7}{5}$
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-c
difficult
q18
asked
Jul 2, 2014
by
thanvigandhi_1
1
answer
Find the equation of the line which passes through the point (– 4, 3) and the portion of the line intercepted between the axes is divided internally in the ratio 5 : 3 by this point
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-b
difficult
q17
asked
Jul 1, 2014
by
thanvigandhi_1
1
answer
A straight line moves so that the sum of the reciprocals of its intercepts made on axes is constant. Show that the line passes through a fixed point. \[\] [ Hint : $\large\frac{x}{a}$$ + \large\frac{y}{b}$$=1$ where $ \large\frac{1}{a}$$+\large\frac{1}{b}$ = constant = $ \large\frac{1}{k}$ (say ). This implies that $ \large\frac{k}{a}$$+\large\frac{k}{b}$$=1 \Rightarrow $ line passes through the fixed point (k, k).]
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-b
difficult
q16
asked
Jul 1, 2014
by
thanvigandhi_1
1
answer
In what direction should a line be drawn through the point (1, 2) so that its point of intersection with the line x + y = 4 is at a distance $ \large\frac{\sqrt 6}{3}$ from the given point
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-c
medium
q15
asked
Jul 1, 2014
by
thanvigandhi_1
1
answer
A variable line passes through a fixed point P. The algebraic sum of the perpendiculars drawn from the points (2, 0), (0, 2) and (1, 1) on the line is zero. Find the coordinates of the point P \[\] [Hint: Let the slope of the line be $m$. Then the equation of the line passing through the fixed point $P (x_1 , y_1 )$ is $y - y_1 = m (x - x_1 )$. Taking the algebraic sum of perpendicular distances equal to zero, we get $ y - 1 = m (x - 1). $ Thus $(x_1 , y_1 ) $ is $(1, 1)$.]
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-a
difficult
q14
asked
Jul 1, 2014
by
thanvigandhi_1
1
answer
If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, – 1), then find the length of the side of the triangle \[\] [Hint: Find length of perpendicular (p) from (2, – 1) to the line and use $p = l \: \sin 60^{\circ}$, where $l$ is the length of side of the triangle]
cbse
math
class11
ch10
straight-lines
exemplar
long-answer-type-question
sec-b
medium
q13
asked
Jul 1, 2014
by
thanvigandhi_1
1
answer
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