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(chatquestion)...llustration 6.96 A person is permitted to select at least one and at most n coins from a collection of (2n + 1) distinct coins. If the total number of ways in which he can select coins is 255, find the value of n. Sol. We have, 2n+C, + 2n+C, + ... + 2n*C, = 255 Also the sum of binomial coefficients is (1) %3D 2nt Cntl "Cy0el 2n+ C, + 2n+C, + … + 2n+lC, + = (1 + 1)²*+1 = 22 %3D %3D = 22n+1 2n+1 C 2n41 Co+2(²n+!C, + 2n\C, + …· + 2n+\ C,) + 1+ 2(zɔɔ) + 1 = 22n + 1+ 255 = 22 22n = 2 or n = 4 ... + ("Ɔ«z+ or %3D or %3D %3D or
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telegram-47197
asked
Jan 23, 2020
by
balaji.thirumalai
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