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Answers posted by priyanka.clay6

2010
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answered Feb 11, 2020
De Broglie wavelength $\lambda = \frac{h}{mv}$$\qquad \lambda = \frac{h}{\sqrt{2 m K}}$$\qquad \larg...
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answered Feb 11, 2020
To get output 1$A = 1 \qquad B = 0 \qquad C = 1$
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answered Feb 11, 2020
Total energy stored in the two capacitor together$\Delta U= \frac{1}{2} C_{eff} \;V^2$$\qquad = \lar...
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answered Feb 10, 2020
$r = $ coefficient of volume expansion $= 5 \times 10^{-4}$$\delta = \delta_o (1+r \Delta T)$$\delta...
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answered Feb 10, 2020
Since the height of water column is greater than length of tube water raises upto top of capillary t...
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answered Feb 10, 2020
$V_I = \text{Input voltage} = v_i = 2\cos[15t+\frac{\pi}{3}]$$A_V=\text{Voltage gain } = 150 =\frac{...
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answered Feb 10, 2020
$\large\frac{I_{max}}{I_{min}} = \begin{bmatrix} \large\frac{\sqrt{\frac{I_1}{I_2}}+1 }{\sqrt{\frac...
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answered Feb 10, 2020
Electric field $E = -(\large\frac{\partial v }{\partial x} \hat{i} + \frac{\partial v}{\partial y} \...
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answered Feb 10, 2020
https://clay6.com/mpaimg/1775_a.jpgAdiabatic has more area under the curve, therefore, this process...
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answered Feb 10, 2020
Temperature of surrounding $= T_1$Temperature of freezer $= T_2 = -20^{\circ}c$$\qquad \qquad \qquad...
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answered Feb 10, 2020
Energy $E = \large\frac{1240\;\;(eV)}{\lambda\;\;(nm)}$ $\qquad \qquad = \frac{1240}{500}$ ...
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answered Feb 8, 2020
$_{92}U^{238 } \to _{90}Th^{234} + 2 He^4$Since momentum is conserved $P_{thorium } = P_{Helium} = p...
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answered Feb 8, 2020
Force on satellite is only gravitational force, which will always be towards the centre of earth.
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answered Feb 8, 2020
Maximum acceleration of $SHM$ is$\qquad \alpha = A w^2 --- (1)$Maximum velocity $\beta = Aw ---(2)$$...
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answered Feb 8, 2020
When negative charge $e^-$ is coming towards loop magnetic flux of one type increased and when going...
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answered Feb 8, 2020
Energy $E = 15\;KeV $$\qquad \qquad = 15 \times 10^3 \;eV$Also $E = \large\frac{12400}{\lambda} \;e...
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answered Feb 8, 2020
${\large\frac{1}{\lambda } }= R Z^2\begin{bmatrix}\large\frac{1}{n_1^2} - \frac{1}{n_2^2} \end{bmatr...
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