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JEEMAIN and NEET
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Physics
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Class11
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Q)
A particle moves in xy plane. The position vector of particle at any time t is
→
r
=
{
(
2
t
)
i
+
(
2
t
2
)
j
}
m
. The rate of change of
θ
at time
t
=
2
seconds is (
θ
is the angle which its velocity vector makes with positive x-axis )
(
a
)
2
17
r
a
d
/
s
(
b
)
1
14
r
a
d
/
s
(
c
)
4
7
r
a
d
/
s
(
d
)
6
5
r
a
d
/
s
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