The e.m.f. of a Daniell cell at 298 K is $E_1$. $Zn/SO_4(0.01 M) || CuSO_4(1.0 M)/Cu$ When the concentration of $ZnSO_4$ is 1.0 M and that of $CuSO_4$ is 0.01 M, the e.m.f. is changed to $E_2$. What is the relationship between $E_1$ and $E_2$ :

Question

( A ) $E_1 < E_2$
( B ) $E_2 = 0 \neq E_1$
( C ) $E_1 = E_2$
( D ) $E_1 > E_2$