If the cube roots of unity are 1, $\omega, \omega^2$, then the roots of the equation $(x-1)^3 + 8 = 0$, are :

Question

( A ) $-1, 1 + 2 \omega, 1 + 2 \omega^2$
( B ) $-1, 1 - 2 \omega, 1 - 2 \omega^2$
( C ) $-1, -1 + 2 \omega, -1 - 2 \omega^2$
( D ) $-1, -1, -1$