# If one of the diameters of the circle, given by the equation, $x^2+y^2−4x+6y−12=0$, is a chord of a circle S, whose centre is at (−3, 2), then the radius of S is :
( A ) $5$
( B ) $5 \sqrt{2}$
( C ) $5 \sqrt{3}$
( D ) $10$