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JEEMAIN-2016
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If one of the diameters of the circle, given by the equation, $x^2 + y^2-4x+6y -12 = 0,$ is a chord of a circle S, whose centre is at $(-3, 2),$ then the radius of S is:
$\begin{array}{1 1}(1) 2 \sqrt 2 \\ (2)5 \sqrt 3 \\(3) 5\\ (4)10 \end{array} $
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